An elevator has a weight limit of 360 .Maximum weight of the people present is 57 and thee minimum is 53.What is the maximum possible number of people present theere
Answers
Answered by
0
Half of them have average weight of 180 and other half has 215.
Maximum Weight is = 2000
So 180*X + 215*X = 2000
=> 395X = 2000
=> X is approximately equal to 5.
So total people is 2*5 = 10
We are not taking 11 as answer because say 11th person has minimum of 180 weight then
180*6 + 215*5 = 2155 (Which is more than 2000)
Maximum Weight is = 2000
So 180*X + 215*X = 2000
=> 395X = 2000
=> X is approximately equal to 5.
So total people is 2*5 = 10
We are not taking 11 as answer because say 11th person has minimum of 180 weight then
180*6 + 215*5 = 2155 (Which is more than 2000)
Similar questions