Question

An elevator is currently 16. 9 feet off the ground. If it ascends (goes up) 32.35 feet, then descends (goes down) 7.8 feet, how far off the ground is the elevator? *


l need this answer now please help me

Answer 1

Answer:

hope its helpful

Step-by-step explanation:

Solution :

Starting position of mine shaft is = 10m above ground

but,

it moves in opposite direction so it travels the distance (-350 m ) below the ground.

Total distance covered by mine shaft = 10m - (-350m)

= 10 + 350

= 360m

Now, taken to cover a distance of 6m by it = 1 minute

Time taken to cover a distance of 1m by it = \frac{1}{6\ }\min

Therefore, tie taken to a cover a distance of 360m = \frac{1}{6}\times\ 360\ =\ 60\ \min\ \

60 minutes = 1 hour

thus, in one hour the mine shraft reaches = 350 below the ground.

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