Physics, asked by dayanandsaraswati74, 4 months ago

. An elevator is going upward with an acceleration 4m/sec2, calculate the
tension in the string of a simple pendulum attached in the elevator, if
its bob is of mass 0.2 kg. (take g = 10 m/sec2.)​
PLEASE DO IT FAST I NEED URGENT SOLUTION

Answers

Answered by Anonymous
18

Answer :

  • The tension of the string is 1.2 N.

Explanation :

Given :

  • Acceleration of the elevator, a = 4 m/s²
  • Mass of the blob, m = 0.2 kg
  • Acceleration due to gravity, g = (-10) m/s²

[Here, the accelaration due to gravity is taken as negative cause the elevator is moving against the gravity]

To find :

  • Tension of the string, T = ?

Knowledge required :

Formula for tension of a string :

⠀⠀⠀⠀⠀⠀⠀⠀T = W ± ma

Where,

  • T = Tension of the string.
  • W = Weight of the object.
  • a = Acceleration of the object.

But we know the formula for Weight of a body i.e,

⠀⠀⠀⠀⠀⠀⠀⠀W = mg⠀

Where,

  • m = mass of the object.
  • W = Weight of the object.
  • a = Acceleration of the object.

So by substituting the equation of Weight of the body in the equation of Tension of the string, we get :

⠀⠀⠀⠀⠀⠀⠀⠀T = mg ± ma⠀

Solution :

By using the equation for tension of the string and substituting the values in it, we get :

⠀⠀=> T = mg - ma

⠀⠀=> T = (0.2 × 10) - (0.2 × 4)

⠀⠀=> T = (2/10 × 10) - (2/10 × 4)

⠀⠀=> T = 2 - 4/5

⠀⠀=> T = (10 - 4)/5

⠀⠀=> T = 6/5

⠀⠀=> T = 1.2

⠀⠀⠀⠀⠀∴ T = 1.2 N

Therefore,

  • Tension of the string, T = 1.2 N


ItzArchimedes: Awesome as always !!
VishalSharma01: Nice :)
Answered by Anonymous
75

 \star\underline{\mathtt\orange{❥Q} \mathfrak\blue{u }\mathfrak\blue{E} \mathbb\purple{ s}\mathtt\orange{T} \mathbb\pink{iOn}}\star\:

An elevator is going upward with an acceleration 4m/sec2, calculate the

tension in the string of a simple pendulum attached in the elevator, if

its bob is of mass 0.2 kg. (take g = 10 m/sec2.)

\star\underbrace{\mathtt\red{❥ᴀ} \mathtt\green{n }\mathtt\blue{S} \mathtt\purple{W}\mathtt\orange{e} \mathtt\pink{R}}\star\:

 { { \underbrace{ \mathbb{ \red{GiVeN\ }}}}}

  •  Acceleration \:of \:the\: elevator(a) =4m/{s}^{2}
  •  Weight \:of \:Bob (m) =0.2kg
  • Acceleration cause of gravity (g) =-10m/{s}^{2}

 (elevator\: is\: moving\: against\: gravity\: so\\ it \:is \:taken \:negative)

{ { \underbrace{ \mathbb{ \red{To\:PrOvE\ }}}}}

  •  Tention \:of\: the \:string (T)

 { \color{aqua}{ \underbrace{ \underline{ \color{lime}{ \mathbb{\star SoLuTiOn\star }}}}}}

{\boxed {\boxed {T=W±ma}}}

  •  T=Tention\: of \:string
  •  W=weight\: of\: the\: object\: (W=mg)

 {\boxed {\boxed {T=mg±ma}}}

 substitute\: the\' values

 T= (0.2\times 10)-(0.2\times 4)

 T= (\frac{2}{10} \times 10)-(\frac{2}{10} \times 4)

 T=2-\frac{4}{5}

 T=\frac{10-4}{5}

 T=\frac{6}{5}

{\boxed {\boxed {\therefore T=1.2N}}}

 Tention \:of\: the\: string\: is {\boxed {\boxed {1.2N}}}

 \blue{\boxed{\blue{ \bold{\fcolorbox{red}{black}{\green{Hope\:It\:Helps}}}}}}

 {\mathbb{\colorbox {orange} {\boxed{\boxed{\boxed{\boxed{\boxed{\colorbox {lime} {\boxed{\boxed{\boxed{\boxed{\boxed{\colorbox {aqua} {@suraj5069}}}}}}}}}}}}}}}

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