Question

An elevator is moving down with a constantacceleration of 1 ms. How much lighterdoes an 80 kg man feel riding the elevator?(A) 60 N(B) 40 N(C) 80 N(D) 20 N​

Answer 1

Answer:

Constant acceleration of an elevator moving downward = 1 m/s²

 

The man inside the elevator weighs = 80 kg

Here, we are required to find the apparent weight of the man i.e., the weight that he will feel while riding the elevator moving downwards.

Thus,  

The apparent weight is given as,

= m(g - a)

= 80 * [0 – (-1)] …… [since the body is moving downwards with a constant acceleartion]

= 80 * 1  

= 80 N