Question

an elevator motor is moving an empty elevator at a speed of 2ms^-1, see diagram above


The electrical power input to the motor is 2kW. The motor is 60% efficient Calculate the magnitude of
the force (friction plus air resistance) against which the motor is working.
​

Answer 1

600N is the magnitude of force against which the motor is working.

It has given that an elevator motor is moving an empty elevator at a speed of 2m/s. the electrical power input to the motor is 2kW. the motor. the motor is 60% efficient.

we have to find the magnitude of the force against which the motor is working.

power = Force × speed

as efficiency of electrical motor is 60%.

so, power = 60% of 2kW = 60/100 × 2 = 1.2 kW = 1200 W

⇒1200 W = force × 2 m/s

⇒force = 600 N

therefore, 600N is the magnitude of force against which the motor is working.

also read similar questions : Working of electric motor of an electric motor

https://brainly.in/question/14125601

An electric motor of power 200 w is switched on for 1 minute and 40 seconds. If 60 percent of the energy of the motor is...

https://brainly.in/question/6771489

Answer 2

$\large \underline{ \blue{ \boxed{ \bf \green{Required \: Answer}}}}$