an elevator of 3×10^4N is raised to a height of 100m in 20s. The work done by electric motor is equivalent to
Answers
Answered by
23
Solution :
• An elevator of 3 × 10⁴ N is raised to a height of 100m in 20s .
We have to find the work done by the electric motor .
• Mass of elevator = 3 × 10⁴N
• g = 10
Work Done = mgh/t
> 3 × 10⁴ × 100 × 10/20
> 3 × 10⁷/20 Joules .
> 1.5 × 10⁶ Joules .
This is the required answer .
_______________________________________
Additional Information -
Work Done = Force × Displacement
Force = Mass × Acceleration
_______________________________________
Answered by
25
Given :-
An elevator of 3×10⁴ N is raised to a height of 100m in 20s.
To Find :-
Work done
Solution :-
We know that
W = mgh/t
W = 3 × 10⁴ × 10 × 100/20
W = 3 × 10⁴ × 10 × 10/2
W = 3 × 10⁴ × 10²/2
W = 1.5 × 10⁶ J
Thereore
Work done is 1.5 × 10⁶ Joules
Similar questions