An elevator of mass 3000 kg starting from rest. How far does it rise in 4 s, if upward tension in supporting cable is 36000 N?
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In the photo u = intial velocity. W = F (weight = Force). g = a = acceleration. s = distance.
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16
Explanation:
Given An elevator of mass 3000 kg starting from rest. How far does it rise in 4 s, if upward tension in supporting cable is 36000 N?
Given mass of elevator = 3000 kg
Also upward tension = 36,000 N
We know that
T – mg = m x a
36000 – 3000 x 10 = 3000 a
36000 – 30000 = 3000 a
3000 a = 6000
So a = 2 m /s
Now u = 0, a = 2, t = 4 s
S = ut + 1/2 at^2
S = 0 + 1/2 x 2 x 4 x 4
S = 16 m
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