An elevator of mass 4000kg is moving upwards and the tensionin the supporiting cable is 40000n . Find the upward acceleration . How far does it raise in a time of 10 starting from rest
Answers
Answer:
Hence the elevator is raised by 10 m
Explanation:
Mass of elevator = 4000 kg
Weight of elevator = Mass × gravity
Weight = 4000 × 9.8
Weight = 39200 N
Upward Force applied = 40000 N
F(net) = 40000 - Weight
F(net) = 40000 - 39200
F(net) = 800 N
Also, F(net) = mass (m) × acceleration (a)
a=800/4000
=>0.2
a=0.2m/s square
initial veocity (u)= 0 m/s
time= 10s
H= ut+1/2 at square
=> H= 0 * 10 + 1/2 0.2 * 10 square
=>H= 0+ 1/2 * 0.2 * 100
=> H = 1/2* 20
=> H= 10 m
Answer:
Hence the elevator is raised by 10 m
Explanation:
Mass of elevator = 4000 kg
Weight of elevator = Mass × gravity
Weight = 4000 × 9.8
Weight = 39200 N
Upward Force applied = 40000 N
F(net) = 40000 - Weight
F(net) = 40000 - 39200
F(net) = 800 N
Also, F(net) = mass (m) × acceleration (a)
a=800/4000
=>0.2
a=0.2m/s square
initial veocity (u)= 0 m/s
time= 10s
H= ut+1/2 at square
=> H= 0 * 10 + 1/2 0.2 * 10 square
=>H= 0+ 1/2 * 0.2 * 100
=> H = 1/2* 20
=> H= 10 m