An elevator plattom is going up at a speed of 20m/s and during the upward motion, a ball of mass
50 g falling in downward direction at a speed of
5m/s. The speed with which the ball rebounds after
an elastic collision with the platform is
(1) 25 ms'
(2) 5 ms-
(3) 45 ms'
(4) 35 ms-
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Answer:
45 ms'
Explanation:
e=v2-v1/u1-u2
u1=-5ms' (negative because ball is moving downward which we are taking as negative)
u2=v2=20ms'
e=1(perfectly elastic collision)
e×(u1-u2)=v2-v1
1×(-5-20)=20-v1
-25=20-v1
v1=20+25
hence, v1=45ms'.
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