Physics, asked by krishnabharti9233, 5 months ago

An elevator weighing 5000 N is raised to a height of 15. 0 m in 10.0 s, how much power is developed

Answers

Answered by sureshkumardas9099
0

Answer:

Elevator weight will be calculated from mg=5000*10=50000newton which will act perpendicular downward. Tension will act perpendicular upward due to thease two forces the resultant force in the body will be accelarating in upward direction it means tension is greater than its weight .we can conclude mathematically

Tension(T)-mg=ma

50000–50000=5000*a from this relation we will get a=0. Now if elevator is moving upward so due to psudo force concept net acceleration will be a+g. But in this case a=0 so net acceleration acting on the elevator is just g.

By the help of newton’s law of motion we can find the distance by using second equation.

S=ut+1/2gt^2

S=0*10+1/2*9.8*10^2

S=490m.

Similar questions