An elevator weighs 3000kg. What is its acceleration when the in the tension supporting cable is 33000N. Given that g = 9.8m/s2.
CLASS - XI PHYSICS (Laws of Motion)
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Answered by
68
M = 3000 kg
g = 9.8 m/s²
T = 33000
a = ?
Ma = Mg - T
3000 * a = 3000 * 9.8 - 33000
3000a = 29400 - 33000
3000a = - 3600
a = - 1.2 m/s²
Therefore, the elevator will move up with an acceleration of 1.2 m/s²
g = 9.8 m/s²
T = 33000
a = ?
Ma = Mg - T
3000 * a = 3000 * 9.8 - 33000
3000a = 29400 - 33000
3000a = - 3600
a = - 1.2 m/s²
Therefore, the elevator will move up with an acceleration of 1.2 m/s²
Answered by
18
M=3000KG a=? tension T=33000N g=9.8m/s2 Ma=Mg-T ie 3000a=3000x9.8-33000 3000a=29400-33000 3000a= -3600 so a= -3600/3000 a=-1.2m/s2
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