Question

An elevator weighs 400 N. When the upward tension in
the supporting cable is 4800 N, what is the upward
acceleration ? Starting from rest, how far does it rise in 3
seconds ?​

Answer 1

I hope this usefull of you

Answer 2

Answer:

given =

weight = 4000Kg ,upwards

tension = 4800 N

to find = upwards tension and distance travelled.

solution,

upwards tension in the supporting cable ,

T = 4800 N

downwards force due to the weight of the elavator,

W = 4000Kg

wt = 4000 X 9.8 N

    = 39200N

net upwards  force on the elavator

W - T  = 39200 - 4800

         =  8800N

now ,

acceleration = a = F/ m

                     =  a = 8800 / 4000

                          a = 2.2 m/s²

now, distance covered by the elavator from rest ,

                s = v t + $\frac{1}{2}$ at²

               s = 1/2 X  2.2 X (3)²

               s = 9.9m