Question

an elevator weight 500kg is to be lifted up at a constant velocity of 0.4m/s. what should be the maximum horse power to be motor used​

Answer 1

Answer:

• 1960 watt is the required answer

Explanation:

Given:-

• Mass ,m = 500 kg
• Velocity ,v = 0.4m/s
• Acceleration due to gravity ,g = 9.8m/s²

To Find:-

• Power of Motor ,P

Solution:-

Firstly we calculate the force applied by the body .

• F = mg

substitute the value we get

→ F = 500 × 9.8

→ F = 50×98

→ F = 4900 N

Now, calculating the Power

• P = F × v

Substitute the value we get

→ P = 4900 × 0.4

→ P = 1960 Watt

• Hence, the power of the elevator is 1960 watt.

Answer 2

Answer:

Given :-

• An elevator weight is 500 kg is to be lifted up at a constant velocity of 0.4 m/s.

To Find :-

• What is the power of the motor to be used.

Formula Used :-

❶ To find force we know that,

★ Force = Mg ★

where,

• M = Mass
• g = Acceleration due to gravity

❷ To find power we know that,

✪ Power = Force × Velocity ✪

Solution :-

❶ First we have to find the force,

Given :

• Mass = 500 kg
• Acceleration due to gravity = 9.8 m/s²

According to the question by using the formula we get,

⇒ F = Mg

⇒ F = 500 × 9.8

➠ F = 4900 N

Hence, the force is 4900 N

❷ Now we have to find the power of a motor,

Given :

• Force = 4900 J
• Velocity = 0.4 m/s

According to the question by using the formula we get,

↦ Power = Force × Velocity

↦ Power = 4900 × 0.4

➦ Power = 1960 W

∴ The power of a motor is 1960 W .