Question

An elevator which can carry a maximum load of 1800 kg (elevator + passengers) is moving up with a

constant speed of 2 ms – 1

. The frictional force opposing the motion is 4000 N. Determine the minimum

power delivered by the motor to the elevator in watt and in horsepower.​

Answer 1

Answer:

59hp

Explanation:

Downward force on the elevator is :  F = mg + f = 22000 N  ∴ Power supplied by motor to balance this force is :  P = Fv = 44000 W

And in horsepower

44000÷746=59 hp

Answer 2

Answer:

Given, the maximum load the elevator can carry isML=1800kg. We know that frictional force always opposes relative motion. So, when the elevator is moving up the frictional force is in downward direction. Hence, Option (B) is correct.

Explanation:

this is the answer