an Elevators deseconds into a mine shaft at the rate of 6m/min . if the descent strats from 10m above the ground level how long will it take to reach -350m
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10 + 350 ÷ 6
360 ÷ 6 = 60
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Answer:
Step-by-step explanation:
Total distance=350+10=360m
Speed of elevator=6*1/60 m/sec=0.1m/sec
Time taken=Distance/Speed
=360/0.1 sec
=3600sec or 1 hr.
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