Math, asked by manjudevi42883, 10 months ago

an Elevators deseconds into a mine shaft at the rate of 6m/min . if the descent strats from 10m above the ground level how long will it take to reach -350m

Answers

Answered by sankars7

2

10 + 350 ÷ 6

360 ÷ 6 = 60

please mark me as brainliest .

Answered by 21shubham

2

Answer:

Step-by-step explanation:

Total distance=350+10=360m

Speed of elevator=6*1/60 m/sec=0.1m/sec

Time taken=Distance/Speed

=360/0.1 sec

=3600sec or 1 hr.

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