an eleverator decends into a mine shaft at the rate of 7m/min if it decends starts from 5m above the ground level how mush will it take to reach -205 m?
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Answer:
at a speed of 7m/min it would take
200/7 min
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Step-by-step explanation:
The distance to be descended by the elevator = (-250) - (+20) = - 270 m
rate = - 9 = (-270) ÷ x
Therefore x = (-270) ÷ (-9)= 30 minutes
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