Question

an elevetor descends into a mine shaft at the rate of 5m/min .If the descent starts from 50m above the ground level;how long will it take to reach -150m​

Answer 1

Answer:

• Time taken by elevator to reach -150 m is 40 minutes.

Step-by-step explanation:

Given that:

• An elevator descends into a mine shaft at the rate of 5 m/min.
• The descent starts from 50 m above the ground.

Note :- Negative distance shows that elevator is going below ground level.

To Find:

• Time taken by the elevator to reach -150 m.

Solution:

Finding total distance covered:

As the elevator starts descending from 50 m above the ground, so the total distance covered will be the sum of 50 m and -150 m. But, distance cannot be negative, so the distance covered will be the sum of 50 and 150.

$\sf{\longmapsto50m+(-150m)}$

As distance can't be negative.

Therefore,

$\sf{\longmapsto50m+150m}$

$\sf{\longmapsto200m}$

Now,

• Distance = 200 m
• Speed = 5 m/min

As we know that:

$\sf{\circ\;Time=\dfrac{Distance}{Speed}}$

Substituting the values,

$\sf{Time=\dfrac{200}{5}\;min}$

Dividing,

$\sf{\longmapsto40\;min}$

Hence,

• Time taken by the elevator to reach -150 m is 40 minutes.