Math, asked by rkjnv723, 1 year ago

An ellipse passing through ( 4√2 , 2√6 ) has foci at ( -4 ,0 ) and ( 4,0 ) . Then, it's accentricity is ____________.


Anonymous: e = Underoot 1 - b^2 / a^2

Answers

Answered by naveen7178
5
take general equation of ellipse
x^2/a^2-y^2/b^2=1
substitute those pts find a,b
the to find e
use formula e=
 \sqrt{1 -  \frac{ {a}^{2} }{{b}^{2} } }
and we also have fociii so
ae=4, we can just direclty find all

naveen7178: fllw me
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