Physics, asked by harishmanhas, 1 year ago

An elrctric bulb is marked
as 240v,60w.the resistance of its filament is

Answers

Answered by rakeshmohata

0

The resistance of its filament R = V²/P=240×240/60 = 4 × 240 =960 ohm (answer)

harishmanhas: true

Answered by Omnamhashivay

0

P=V^2/R
R=V^2/P
=240×240/60=240×4=960ohm

harishmanhas: yes

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