Question

An elvator descends into mine shaft at rate of 6m/mm.If the descends starts from 10m above the ground level, how long will take to reach -350m.

Answer 1

Answer:

60mm

Step-by-step explanation:

Total distance = 10+350=360 m

speed =6m/mm

Hence time = distance ÷ speed

putting values in the equation gives the answer

360÷6 = 60mm.