Question

an elveter descends into a mine shaft at rate 6 m/min . the descents starts from 10 m above sea level. where will it take to reach in 20 min. how long will it take to reach depth of -350m?​

Answer 1

Ello user !!!!!!!

Here is your answer,

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Distance descended is denoted by a negative integer.

Initial height = +10 m

Final depth = −350 m

Total distance to be descended by the elevator = (−350) − (+10) = −360 m

Time taken by the elevator to descend −6 m = 1 min

Thus, time taken by the elevator to descend −360 m = (−360) ÷ (−6)

= 60 minutes = 1 hour

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