an empty can of mass 3m has mass distribution as shawn in fig .it rolls withiut slipping on ahorizontal surface with centre of mass velocity v and total K.E nmv^2÷2.Find value of n?
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hi frnd
Total kinetic energy = linear kinetic energy + rotational kinetic energy
=
moment of inertia of annular disc ,
=
given, velocity of centre of mass is v
in rolling motion,
so, v = 2r
hence, = v/2r
now, total kinetic energy = 1/2 mv² + 1/2 × 5/2 × mr² × (v/2r)²
= 1/2 mv² + 5/16 mv²
= (13/16) mv²
HOPE THIS HELPS YOU
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