Question

an empty can of mass 3m has mass distribution as shawn in fig .it rolls withiut slipping on ahorizontal surface with centre of mass velocity v and total K.E nmv^2÷2.Find value of n?​

Answer 1

hi frnd

Total kinetic energy = linear kinetic energy + rotational kinetic energy

=

moment of inertia of annular disc ,

=

given, velocity of centre of mass is v

in rolling motion,

so, v = 2r

hence, = v/2r

now, total kinetic energy = 1/2 mv² + 1/2 × 5/2 × mr² × (v/2r)²

= 1/2 mv² + 5/16 mv²

= (13/16) mv²

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