Question

An empty cistern can be filled by two taps A and B in 12 minutes and 16 minutes,
respectively, and the full cistern can be emptied by a third tap C in 8 minutes. If all the
three taps are turned on simultaneously, in how much time will the empty cistern be
full?​

Answer 1

Time taken by tap A to fill the cistern = 12 hours.

Time taken by tap B to fill the cistern = 16 hours.

Time taken by tap C to empty the full cistern = 8 hours.

A’s 1 hour’s work = ¹/₁₂

B’s 1 hour’s work = ¹/₁₆

C’s 1 hour’s work = −1/9 (cistern being emptied by C)

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