Question

An empty cistern can be filled by two taps A and B in 12 minutes and 16 minutes,
respectively, and the full cistern can be emptied by a third tap C in 8 minutes. If all the
three taps are turned on simultaneously, in how much time will the empty cistern be full?​

Answer 1

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Answer 2

Answer:

Step-by-step explanation:

A's one minute work is 1/12

B's one minute work is 1/16

C's one minute work is 1/8

By the problem

1/12 + 1/16 - 1/8

LCM

4/48 + 3/48 - 6/48

7/48 - 6/48

1/48

Means 48 minutes

The empty cistern will be filled in 48 minutes

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