Math, asked by ravi2070, 1 year ago

An empty cistern can filled by two taps A and B

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Answered by Anonymous
3

Step-by-step explanation:

1/12+1/16-1/8=1/time

(4+3-6)/48=1/T

1/48=1/T

therefore time to fill the cistern is 48 min if 3 taps are opened simultaneously.


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