Question

An empty metal container (without its handle) weight 15% of its weight when filled with a particular liquid. after adding the handle, the weight of the fully filled container increases by 5%. if the weight of a partly filled container is 1/3 of the completely filled container with handle attached, then what fraction of container is utilized

Answer 1

Suppose a full container without the handle weighed 100g

then the container would weigh 15g and the liquid 85g.

Now, adding a handle adds 5% or 5 grams,

So a full container with a handle would weight 15g + 85g + 5g = 105g

1/3 of this total is 1/3 (105) = 35g

subtracting the weights of container and the handle we get

35g - 5g - 15g = 15g

Now calculating our fraction we have,

15 / 85 = 3 / 17

Therefore 3 /17 of the container is utilized.

Answer 2

Answer: The answer to the following question according to me is 4/17 contrary to the previous answer in the following thread.

Step-by-step explanation:

We know,

Weight of filled container without handle= W (assuming)

Next we have weight of empty container without handle= 15% of W = 0.15W

Weight of filled container with handle= 105% (i.e % extra) of W = 1.05W

Next Weight of container with *handle* = (1.05W-0.85W) = 0.2W

Now comes the tricky language part of the question. It clearly says weight of partly filled container (does not mention with *handle*) is 1/3 of {Completely filled container *with handle* attached).

=1/3 (1.05W) = 0.35W

Fraction of container utilized

=(Weight of partly filled container - Weight of empty container without handle)/(Weight of liquid when fully filled)

= (0.35W- 0.15W)/ (W- 0.15W)= 4/17

Hence the answer is 4/17