Question

An empty RD bottle has a mass of 100 g. When filled with water, the bottle has a mass of 200 g, and 181 g when filed with kerosene. Find volume of the bottle and RD of kerosene​

Answer 1

Answer:

Solution:

Density of water = 1 g cm³

(a) Volume of density bottle

Mass of empty density bottle = M1 = 21.8g

Mass of bottle + water = M2 = 41.8g

So, mass of water completely filling the density bottle = M2-M1

= 41.8 - 21.8 = 20g

1g of water has volume =cc

So, Volume of bottle = volume of water = 20cc = 20ml

(b) The relative density of liquid

Mass of 20 cc of liquid

= (mass of density bottle + mass of 20cc of liquid) - mass of density bottle

= 40.6 - 21.8

= 18.8 g

Mass of 20 cc of water = 20g

Relative density of liquid

R.D = \frac{Mass\ of\ 20\ cc\ of\ liquid}{Mass\ of\ 20\ cc\ of\ water}=\frac{18.8}{20}=0.94\

Mass of 20 cc of water

Mass of 20 cc of liquid

=

20

18.8

=0.94

Answer 2

$\huge{\pink{\boxed{\orange{\bf{Solution:}}}}}$

Density of water = 1 g cm³

${\pink{\boxed{\orange{\bf{(a) \:Volume\: of\: density\: bottle}}}}}$

Mass of empty density bottle = M1 = 21.8g

Mass of bottle + water = M2 = 41.8g

So, mass of water completely filling the density bottle = M2-M1

= 41.8 - 21.8 = 20g

1g of water has volume =cc

So, Volume of bottle = volume of water = 20cc = 20ml

${\pink{\boxed{\orange{\bf{(b)\: The\: relative\: density\: of\: liquid}}}}}$

Mass of 20 cc of liquid

= (mass of density bottle + mass of 20cc of liquid) - mass of density bottle

= 40.6 - 21.8

= 18.8 g

Mass of 20 cc of water = 20g

Relative density of liquid

$R.D = \frac{Mass\ of\ 20\ cc\ of\ liquid}{Mass\ of\ 20\ cc\ of\ water}=\frac{18.8}{20}=0.94\}$

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