Physics, asked by SAGITTARIUS12, 10 days ago

An empty RD bottle has a mass of 25.25 g. when filled with water, the bottle has a mass
55.75 g, and 45.50 g when filled with alcohol. Find the (i) volume of the bottle, (ii) RD
Of alcohol, and (iii) density of alcohol.

Answers

Answered by saisanat2010
2

Answer:

Considering:

mass of empty RD bottle: 25.25 g

mass of bottle filled with water: 55.75 g ⇒ mass of water: 55.75 - 25.25 = 30.5 g

mass of bottle filled with alcohol: 45.50 g ⇒ mass of alcohol: 45.50 - 25.25 = 20.25 g

Volume of bottle (Just for reference, you will not use it):

V=\frac{1}{3} \pi h_{2} (a^{2} +ab+b^{2} )+\pi b^{2} h_{2}V=

3

1

πh

2

(a

2

+ab+b

2

)+πb

2

h

2

aa : neck radius

bb : body radius

h_{2}h

2

: neck height

h_{1}h

1

: body height

RD = \frac{\rho Substance}{\rho Reference}RD=

ρReference

ρSubstance

Density (\rho)= \frac{Mass (m)}{Volume (V)}Density(ρ)=

Volume(V)

Mass(m)

Density of water = 1 g/mL

1 = 30.5 V1=30.5V

V = \frac{1}{30.5}mlV=

30.5

1

ml

Therefore the Volume of bottle is \frac{1}{30.5}ml

30.5

1

ml

The density of alcohol is:

DensityAlcohol (\rho)= \frac{20.25}{\frac{1}{30.5}}DensityAlcohol(ρ)=

30.5

1

20.25

DensityAlcohol (\rho)= 617.625 g/cm3DensityAlcohol(ρ)=617.625g/cm3

RDAlcohol = \frac{617.625}{1} = 617.625 g/cm3RDAlcohol=

1

617.625

=617.625g/cm3

Answered by WantCorrectAnswer
1

SOLUTION:

Mass of the empty R.D bottle (m1) = 22.25 g

Mass of R.D bottle filled with water (m2) = 55.75 g

Mass of R.D bottle filled with alcohol (m3) = 45.50 g

Mass of alcohol = (m3 - m1) = (45.50 - 25.25) g

Mass of water = m2-m1 = (55.75 - 25.25) g = 30.50 g

i)

As the density of water is 1g/cm³, so the volume of water in the bottle is 30.50 cm³. This means that the volume of the bottle is 30.50 cm³.

OR

i)

Density =  \frac{Mass}{Volume}

➡ Volume =  \frac{Mass \: of \: water}{Density  \: of \:  water}

➡ Volume = ( \frac{30.50}{1}) \: cm³ \:  = 30.50 \: cm³

iii)

R.D of Alcohol = \frac{ m3 - m1}{m2-m1}

=  \frac{20.25 \:g}{30.50 \: g}  =  \: 0.66

ii)

R.D of alcohol =  \frac{Density \:  of \:  alcohol}{Density \:  of \:  water \:  at  \: 4° C}

Density of alcohol = R.D of alcohol × density of water at 4° C

= 0.66 × 1 g/cm³ = 0.66 g/cm³

____________________________________________

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