An empty tank can be filled up in 1 hour 20 minutes by 6 pipes. If 5 similar pipes are used, how much time will be required to fill up the tank?
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Answer:
Let the desired time to fill the tank be x minutes.
In 80 mins a tank is filled by 6 pipes
Lesser the number of pipes more will be the time required by it to fill the tank.
So, this is a case of inverse proportion.
Hence, 80×6=x×5
⇒
5
80×6
=x
⇒x=96
Thus, the time is taken to fill the tank by 5 pipes is 96 minutes or 1 hour 36 minutes.
Step-by-step explanation:
Answered by
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this is a case of inverse proportion
no of pipes time taken
6. 80min
5. x (let)
therefore
6/5 = x / 80
x = 6×80/ 5
= 6×16
= 96 min
= 1 hr 36 min
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