Math, asked by suchitadebnath77, 20 days ago

An empty tank can be filled up in 1 hour 20 minutes by 6 pipes. If 5 similar pipes are used, how much time will be required to fill up the tank?​

Answers

Answered by prateek8r422
0

Answer:

Let the desired time to fill the tank be x minutes.  

In 80 mins a tank is filled by  6 pipes

Lesser the number of pipes more will be the time required by it to fill the tank.  

So, this is a case of inverse proportion.

Hence, 80×6=x×5  

⇒  

5

80×6

=x

⇒x=96  

Thus, the time is taken to fill the tank by 5 pipes is 96 minutes or 1 hour 36 minutes.  

Step-by-step explanation:

Answered by sharmadhruv70141
0

this is a case of inverse proportion

no of pipes time taken

6. 80min

5. x (let)

therefore

6/5 = x / 80

x = 6×80/ 5

= 6×16

= 96 min

= 1 hr 36 min

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