An empty truck of weight 4000n moving with a velocity of 72 Km/H. Finds its acceleration
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Answered by
1
t=distance × speed
t = 4000× 72
t= 36000
then ,
a =v-u/t
a= 72 - o / 10
a= 7.5
t = 4000× 72
t= 36000
then ,
a =v-u/t
a= 72 - o / 10
a= 7.5
do you know the question???
4000 is not speed .its weight
Answered by
0
t=distance × speed
t = 4000× 72
t= 36000
then ,
a =v-u/t
a= 72 - o / 10
a= 7.5
hope this may help.....
here weight is given as 4000N .how can you use it as distance ..
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