Question

an empty truck weighs 4000n.its engine can produce a maximum acceleration of 1m/s^2.if the truck is loaded with 2000n,find the maximum acceleration the engine can produce.

Answer 1

Answer:

Here is your answer mate

Explanation:

F = m a

F = (4000/g)(1) = 4000/g Newtons

same F but now mass is 6000/g

4000/g = (6000/g) a

a = 4/6 = .67 m/s^2

Please follow and mark as brainliest

Answer 2

Answer:

here's the answer.

Explanation:

Data:

Weight of empty truck = 4000 N

Mass of empty truck = m¹= 4000/10 = 400 kg

Mass of load = 2000N/10 = 200kg

Mass loaded truck = m² = m¹ + 200

m² = 400 + 200

m² = 600

Acceleration of empty truck = a¹ = 1 m/s

Acceleration of loaded truck = a² = ?

SOLUTION:

F¹= m¹a¹

F¹ = 400 × 1

F¹ = 400 N (dragging force)

F² = m²a²

F² = 600 × a²

F¹ = F²

400 = 600 a²

400/600 = a²

a² = 0.66 m/s²