Question

an enantiomerically pure acid is treated with racemic mixture of alcohol having one chiral carbon,the ester formed will be​

Answer 1

The enatiomerically pure acid or optically active acid will react with both the forms (d and l) of the alcohol in the racemic mixture to form isomeric pair of esters. In each isomer the configuration of the chiral center(carbon) remains the same , so the mixture will be optically active. May be correct answer

Answer 2

Answer:

Explanation:

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