Question

An energy meter having a meter constant of 1200 rev/kwh is found to make 5 revolutions in 75 seconds. The load power is

Answer 1

Answer:

Explanation:

In this type of questions formula is not applicable for solve this question we use dimensions and unitary methods

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Answer 2

The load power is 200 Watt.

Explanation:

Given that,

Energy = 1200 rev/kw h

We need to calculate the load power

Using unit method,

1200 rev/ kw h means

1200 rev = 1 kwh

$1\ rev = \dfrac{1\times10^{3}\times3600}{1200}$

Load power found to make 5 revolution in 75 sec,

$1\ rev= \dfrac{5\times1\times10^{3}\times3600}{1200\times75}$

$1\ rev =200\ W$

Hence, The load power is 200 Watt.

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Topic : power

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