Question

An energy of 84000 J is required to raise the temperature of 3 kg of water from 330 K to 360 K. Calculate the specific heat capacity of water.

Answer 1

Answer:

Given:

mass(m)=1kg

Heat energy required (Q)=?

Rise in temperature Δt=100−20=80∘C=80K

Specific heat capacity (c) 483Jkg−1K−1

Specific heat capacity (c) =Mass(m)×RiseintemperatureHeatenergy(Q)

483=Q/(1×80)

Q=38640J