An energy source forces a constant current of 2A for 10s to flow through a lightbulb. If 2.3 kJ is given off in the form of light and heat energy, the voltage drop across the bulb is?
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=115V is the correct answer
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Answer:
115 V
Explanation:
The total charge is
∆q = i ∆t = 2 × 10 = 20 C
The voltage drop is
v = ∆w/ ∆q
= 2.3 × 10^3 / 20
= 115 V
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