) An Engine applies 800 N of force to run a train of 5 wagons. How much should be the frictional force
exerted to stop the train?
a. 800 N b. 4000 N c. -850 N d. 0N
Answers
Answer:
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Force and Laws of Motion
NCERT Exercise Solution - part 2
Question 7: A 8000 kg engine pulls a train of 5 wagons, each of 2000 kg, along a horizontal track. If the engine exerts a force of 40000 N and the track offers a friction force of 5000 N, then calculate:
(a) the net accelerating force;
(b) the acceleration of the train; and
(c) the force of wagon 1 on wagon 2.
Answer: Given, force of engine = 40000 N
Force of friction = 5000 N
Mass of engine = 8000 kg
Total weight of wagons = 5 x 2000 kg = 10000 kg
(a) The net accelerating force
= Force exerted by engine – Force of fricition
= 40000 N – 5000 N = 35000 N
(b) The acceleration of the train
We know that, F = mass x acceleration
Or, 35000 N = (mass of engine + mass of 5 wagons) X a
Or,
35000
N
=
(
8000
k
g
+
10000
k
g
)
×
a
Or,
35000
N
=
18000
k
g
×
a
⇒
a
=
35000
N
18000
k
g
=
1.944
m
s
−
2