Physics, asked by solankem3119, 6 days ago

An engine can pump 26,892 litres of water to a vertical height of 16m in 3.5 minutes. Calculate the work done by the engine and its power. (g = 9.8 m s-2, density of water = 1000 kg m-3)

Answers

Answered by mahanteshgejji
0

Answer:

Work done = 4216 kJ

Power of pump = 20 kW

Explanation:

Volume of water lifted V = 26892 lites = 26892 x 10⁻³ m³

Mass of water lifted m = ρV = 1000 x 26892 x 10⁻³ = 26,892 kg

Work done W.D = mgh = 26892 x 9.8 x 16 J

                                       = 4216665.6 J

                                       = 4216.67 kJ

Power of pump  P = W/t = 4216665.6/ (3.5 x 60)

                                     = 20007.9 W

                                     = 20 kW

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