An engine is moving with a velocity 44 m/s
After applying the brakes it stops after
covering a distance of 121 m .Calculate
retardation and time taken by
the engine to stop
Answers
Answered by
6
Answer:
936=2@121
@=968/121=8
retardation is 8 m/s²
44=8t
t=5.5s
time is 5.5s
Step-by-step explanation:
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Answered by
5
Answer:
Step-by-step explanation:1936=2@121
@=968/121=8
retardation is 8 m/s²
44=8t
t=5.5s
time is 5.5s
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