Question

An engine is rotating at the rate of 1500 RPM. Find its angular velocity

57.1 rad/sec

none of above

257.1 rad/sec

1571 rad/sec​

Answer 1

Answer:

Answer

Deceleration can be found by using the equation of motion

ω=ω

0

+αt

⟹α=−

t

ω

0

=−

15×60

100

rev/s

2

=−

9

1

rev/s

2

Now using the equation of motion:

ω

2

−ω

0

2

=2αθ

⟹θ=

2α

ω

0

2

=12.5