An engine is used to fill a tank by taking water from a depth of 80 m. If the average horsepower of the engine is 3500 and its efficiency is 75% then how much water passes through the pipe in one hour?( g= 10m/s^2) Ans- 88.5 * 10^5 kg)..................how????....please answer
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Answer:
Let Volume of Tank be V
pipe A can fill the tank
6
V
in 1 Hour
pipe B can fill the tank
8
V
in 1 Hour
Let us assume that C can fill the tank
C
V
in 1 Hour
and we need to fill the tank
2
V
in 1 Hour as we have to fill the complete tank in 2 Hrs
⇒
6
V
+
8
V
+
C
V
=
2
V
⇒
6
1
+
8
1
+
C
1
=
2
1
solving we get C=
5
24
hrs
Rate of Pumping is
5
24
V
Time to fill the Tank when C is used alone=
5
24
=4.8hrs
Explanation:
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