Question

An engine jack is used to lift a 200-lb engine 4'. How much work is performed?

Answer 1

ANSWER WITH EXPLAINATION

Answer 2

Work done is 800 J.

Given :

Force = 200N

Distance = 4m

To find :

The work done

Solution :

We know that work done = force * time taken.

Let W be the work done.

W = F * D

W = 200 *  4m

W = 800 J.

Thus, the work done is 800 J.

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