Physics, asked by Anonymous, 3 months ago

An engine of a train, moving with uniform acceleration, passes the signal post with velocity u and the last compartment with velocity v. The velocity with which middle point of the train passes the signal post is:​

Answers

Answered by vaishnavibarad8
1

Answer:

(1) length of train :- l

When last compartment passes through pole distance covered by first compartment is l

∴v

2

=u

2

+2al

∴a=

2l

v

2

−u

2

Now, when middle post passes, distance covered by first compartment is

2

l

∴v

f

2

=u

2

+

2

Ral

=u

2

+(

2l

v

2

−u

2

)l=

2

v

2

+u

2

∴v

f

∴v

f

2

=u

2

+

2

Ral

=u

2

+(

2l

v

2

−u

2

)l=

2

v

2

+u

2

∴v

f

=

2

v

2

+u

2

Explanation:

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