Question

An engine of a vehicle can produce a maximum
acceleration of 4 ms 2. Its brakes can produce a
maximum retardation of 6 ms-2. The minimum
time in which it can cover a distance of 3 km is:
(a) 30 s (b) 40 s (c) 50 s (d) 60 s​

Answer 1

Answer:

maximum acceleration =4m/s²

maximum reduction =6m/s²

distance =3km

__αβ__

[2(α+β)] ×t²=S

α= maximum acceleration

β= maximum reduction

t= time

S= distance

t² = 2500

t= 50 sec