Question

An engine operates between temperatures limits of 900k and t2 and another between t2 and 400k for both to be equally efficient the value of t2 will be

Answer 1

Explanation:

both engines to do equal work.

so w1=w2

net work1= t1-t2

= 900-t2

net work2= t1-t2

= t2-400

900-t2=t2-400

1300=2t2

t2=650.

Answer 2

Thus the value of t2 will be 650.

Explanation:

We are given that:

• Temperature T1 = 900 K
• Temeprature T2 = 300 k

Solution:

As both engines has done equal work.

Now w1 = w2

Net work1= t1-t2

= 900-t2

Net work 2= t1-t2

= t2-400

900 - t2 = t2 - 400

1300 = 2t2

t 2 = 650

Thus the value of t2 will be 650.