An engine operates between temperatures limits of 900k and t2 and another between t2 and 400k for both to be equally efficient the value of t2 will be
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Explanation:
both engines to do equal work.
so w1=w2
net work1= t1-t2
= 900-t2
net work2= t1-t2
= t2-400
900-t2=t2-400
1300=2t2
t2=650.
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Thus the value of t2 will be 650.
Explanation:
We are given that:
- Temperature T1 = 900 K
- Temeprature T2 = 300 k
Solution:
As both engines has done equal work.
Now w1 = w2
Net work1= t1-t2
= 900-t2
Net work 2= t1-t2
= t2-400
900 - t2 = t2 - 400
1300 = 2t2
t 2 = 650
Thus the value of t2 will be 650.
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