an engine pulls a body of mass 1000kg on a level road at a constant velocity of 8m/s. If the frictional force is 400N, what power does the engine generate?
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Hola User_________________
Here is Your Answer....!!!!
_________________________〽
⭐Actually welcome to the concept of the Power and Energy...
⭐Basically we know that. ...
⭐Power is work Done per unit time ......
⭐Also we know that
⭐Power = Force × Velocity. ..
thus applying here we get ....
⭐Power = 400 × 8
⭐Power = 3200 joules ....
⭐Thus as here the Frictional force = the applied force ....
the normal gets balanced with the mg ....
____________________________〽
Hope it helps u.....☺
Here is Your Answer....!!!!
_________________________〽
⭐Actually welcome to the concept of the Power and Energy...
⭐Basically we know that. ...
⭐Power is work Done per unit time ......
⭐Also we know that
⭐Power = Force × Velocity. ..
thus applying here we get ....
⭐Power = 400 × 8
⭐Power = 3200 joules ....
⭐Thus as here the Frictional force = the applied force ....
the normal gets balanced with the mg ....
____________________________〽
Hope it helps u.....☺
Anonymous:
Halo ruth aajkal ta ta mo sita dher boldinas ta k vyo?
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