Question

an engine pulls a car of mass 1500kg on a level road with a constant speed 5m/s.The extra power must the engine develop to maintain the same speed up an inclined plane having a gradient of 1 in 10 is​

Answer 1

Answer:

Please refer work, power, energy related numericals

for this questions

wt.of car =1500Kg

constant speed of car =5.0ms

−1

then total force by the car to move for work =total force by engine + frictional force

=1500×5+500

f

1

=7500+500

f

1

=8000N≈

f

1

=8KN

Total work done =w

1

=F

1

×v=8000×5

W

1

=40,000watt

w

1

=40kw

case II

⇒ gradient 1 in 10 means

then sinθ=

10

1

.

Total Applied force =Mgsinθ+Frictionalforce

F

2

=1500×9.8×

10

1

+500

AB=10

BC=1

F

2

=1970N

total work done w

2

=1970×5=9850walr

extra or 9.850Kw

Total work done w=w

1

+w

2

=40+9.85=49.85