Physics, asked by daliyabanerjee150349, 10 months ago

an engine pumps 100kg of water per minute from a well through an average height of 12m. Find the power of engine if the engine is only 40% efficient. Take g =10m/se
answer is 5kw​

Answers

Answered by Anonymous
201

\huge\underline{\underline{\bf \orange{Question-}}}

An engine pumps 100kg of water per minute from a well through an average height of 12m. Find the power of engine if the engine is only 40% efficient.

Take g =10m/

\huge\underline{\underline{\bf \orange{Solution-}}}

\large\underline{\underline{\sf Given:}}

  • Engine pumps water=100 kg/m
  • Average Height = 12m
  • Efficiency {\sf (\eta)}=40%
  • g = 10m/s²

\large\underline{\underline{\sf To\:Find:}}

  • Power of engine .

\large{\boxed{\bf \blue{Power(P)=\dfrac{Work}{Time}}}}

\implies{\sf P=\dfrac{mgh}{t}}

\implies{\sf P = 100×10×12 }

\implies{\sf P=12kW }

\large{\boxed{\bf \blue{Effective\:Power(P')=\eta × P }}}

\implies{\sf P'=\dfrac{40}{100}×12 }

\implies{\sf P'=\dfrac{24}{5} }

\implies{\bf \red{P'≈5kW}}

\huge\underline{\underline{\bf \orange{Answer-}}}

Power of engine if the engine is only 40% efficient is {\bf \red{5kW}}

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