An engine pumps out 475 L of water in 1
min. How much time will be taken by it to
jump out 1396500 L of water? with explanation
(a) 50 h
(b) 54 h
(c) 49 h
(d) 47 h
Answers
Answered by
11
Answer:
50h
Step-by-step explanation:
a engine pump 475lts in 1min
1min =457
xmin=1396500lts
1396500÷457=3055.72min
in hrs 50hrs
Answered by
21
Answer:
hey mate here is your answer
Step-by-step explanation:
time taken to pump out 475L = 1 min
time taken to pump out 1L = 1/475 min
total volume of water = 1396500L
time taken to pump out 1396500L =
= 1/475 ×1396500 min
= 1 × 2940 min
= 2940 min
= 2940/60 hr
= 49 hr
hope this helps you.........
please mark it as brainliest
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