an engine pumps up 100 kg of water through a height of 10 metre in 5 sec if the efficiency is 60% calculate the power of engine in kW
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11
Output power = mgh/t
= 100 kg × 10 m/s² × 10 m / 5 s
= 2 × 10³ Watt
= 2 kW
Effeciency = [(Output power) / (Input power)] × 100
60 = [2 kW / (Input power)] × 100
Input power = 3.33 kW
Power of engine is 3.33 kW
= 100 kg × 10 m/s² × 10 m / 5 s
= 2 × 10³ Watt
= 2 kW
Effeciency = [(Output power) / (Input power)] × 100
60 = [2 kW / (Input power)] × 100
Input power = 3.33 kW
Power of engine is 3.33 kW
Answered by
1
p=mgh/t
100*10*10/5
2*10³
2kw
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