Question

an engine pumps up 100 kg of water through a height of 10 m in 5 seconds if the efficiency of the engine is 60% calculate the power of the engine in kW

Answer 1

Output power = mgh/t
= 100 kg × 10 m/s² × 10 m / 5 s
= 2 × 10³ Watt
= 2 kW

Effeciency = [(Output power) / (Input power)] × 100
60 = [2 kW / (Input power)] × 100
Input power = 3.33 kW

Power of engine is 3.33 kW

Answer 2

p1=w/t
=mgh/t
=100×10×10/5s
=10000/5
=2000w
=2Kw
efficiency=[p1/p2]×100
60=[2/p2]×100
p2=3.33Kw